Re: PHP Warning: parse_url
I pasted the code with an error in it. Use this function instead:
function bb_get_path( $level = 1, $base = false, $request = false ) {
if ( !$request )
$request = $_SERVER;
if ( is_string($request) )
{
// parse_url throws a warning for a url that has http:// as a query parameter and doesn’t start with http://
$pos = strpos($request, “http://”);
// Check if we found http:// in the string and it’s not at the beginning, and the url starts with a forward slash
if ($pos !== false && $pos > 0 && substr($request,0,1) == “/”)
{
// We got here, so it’s not at the beginning and is in the url. Add in the domain to the beginning
$oldRequest = $request; // Use a new variable since some PHP versions don’t like re-assigning
$request = “http://”.$_SERVER[“HTTP_HOST”].$oldRequest;
}
$request = parse_url($request);
}
if ( !is_array($request) || !isset($request) )
return ”;
$path = rtrim($request, ” tnrx0B/”);
if ( !$base )
$base = rtrim(bb_get_option(‘path’), ” tnrx0B/”);
$path = preg_replace(‘|’ . preg_quote($base, ‘|’) . ‘/?|’,”,$path,1);
if ( !$path )
return ”;
if ( strpos($path, ‘/’) === false )
return ”;
$url = explode(‘/’,$path);
if ( !isset($url[$level]) )
return ”;
return urldecode($url[$level]);
}