[Null]

Ok, I have searched the net for hours, but I couldn’t get an answer for my question.

If we use the for “each function” in php we can get a list of items like:

Jack

John

Adrian

Etc

But the first name a want to have bold so it looks like:

Jack

John

Adrian

Etc

Best way for me to do this, is to ad a class to the first name in the php code. But how do I do this? Cause the “for each” generates a list that is the same for eacht row (php/html code wise). So I only want the first name to be bold using a class (from a css) but all others not effected.

Thx

[ear1grey]

$class="special";

foreach($foo as $bar) {

echo("<p class='$class'>$bar</p>);

$class="";

}

[chrishajer]

That is a very interesting short circuit. Thanks for that one ear1grey.

[Null]

Euuhh well still can’t get it to work…

I have the function:

function get_bb_menu() {

global $bbdb;

return $bbdb->get_results("SELECT * FROM $bbdb->menu WHERE set = 'active' ORDER BY order ASC");

}

This will give (tabel sperated with – ):

set – item – page – is – order

active – Forums – index.php – is_front() – 0

active – Statistic – statistics.php – is_bb_stats() – 1

active – Search – search.php – is_bb_search() – 2

Now I want this in a for each so it generates (note this is A PART what it should generate):

<li><a <?php if (is_bb_search())

{

echo "id="current"";

}?> href="<?php option('uri'); ?>search.php">Search</a></li>

<li><a <?php if (is_bb_stats())

{

echo "id="current"";

}?> href="<?php option('uri'); ?>statistics.php">Statistics</a></li>

But how to do this???

[ear1grey]

That’s very difficult to decipher, so for maintainability may I suggest you break out the code so you create variables first then use them when creating the echo statement.

It looks like you need to use call_user_func(tabel["is"]) to run the function names that you’re retrieving from the db.

[Null]

I did that but you can’t use php in an echo:

<?php

global $bbdb;

$r = mysql_query("SELECT * FROM $bbdb->menu WHERE set = 'active' ORDER BY order ASC");

while($rw = mysql_fetch_array($r))

{

echo '<li><a href="'.$rw['page'].'">'.$rw['item'].'</a></li>';

}

?>

This works perfectly, but now I want to add some php code into <a!here the php code!>...</a> so it will look like this (i only show the echo now):

{

echo<li><a <?php if ('.$rw['is'].')

{

echo "id="current"";

}?> href="<?php option('uri'); ?>'.$rw['page'].'">'.$rw['item'].'</a></li>;

}`

But this aint working cause you cant do php in an echo. Any suggestions?

[ear1grey]

Just compute the computable stuff beforehand and it becomes a lot more maintainable/readable.

// setup the basic data

$uri=option("uri").$rw["page"];

$class="";

// compute the computable data

if ($rw['is']) { $class="current" }

// write the line

echo "<li><a class='$current' href='$uri'>".$rw['item']."</a>"

Note that I’ve used class rather than id for semantic purposes – the ID of an element shouldn’t change, but it’s class can change and can be multiple, so you could even do:

$class="item";

if ($rw['is']) { $class .=" current" }

[Null]

Hmm got this now:

<?php

global $bbdb;

$r = mysql_query("SELECT * FROM $bbdb->menu WHERE set = 'active' ORDER BY order ASC");

while($rw = mysql_fetch_array($r))

$class="";

if ($rw['is']) { $class .=" current" }

{

echo '<li><a class="$current" href="'.$rw['page'].'">'.$rw['item'].'</a></li>';

}

?>

But this gives me an error:

Parse error: parse error, unexpected ‘}’ on line 71

Think I have misplaced something here?

Greetz

ps I didn’t include $uri=option("uri").$rw["page"]; at all cause I wanted to test this first. So I keep it out for now…

[ear1grey]

the while looks like it needs curly brackets adding to it or you’re just going to repeatedly set $class="" then remove the curly bracket above the echo.

[Null]

Can you give me a code example, cause i keep getting the error

[ear1grey]

<?php

global $bbdb;

$r = mysql_query("SELECT * FROM $bbdb->menu WHERE set = 'active' ORDER BY order ASC");

while($rw = mysql_fetch_array($r)) <strong>{</strong>

$class="";

if ($rw['is']) { $class .=" current" }

echo '<li><a class="$current" href="'.$rw['page'].'">'.$rw['item'].'</a></li>';

}

?>

[Null]

Still no luck

I have this:

<?php

global $bbdb;

$r = mysql_query("SELECT * FROM $bbdb->menu WHERE set = 'active' ORDER BY order ASC");

while($rw = mysql_fetch_array($r))

{

$class="";

if ($rw['is']) { $class .=" current" }

echo '<li><a class="$current" href="'.$rw['page'].'">'.$rw['item'].'</a></li>';

}

?>

Which is the same code as yours, but I still get the error:

Parse error: parse error, unexpected '}' on header.php on line 84

And line 84 contains the if:

if ($rw['is']) { $class .=" current" }

I am totally lost here :S

[ear1grey]

...current"; }

i.e.

...current"SEMICOLON }

?

[Null]

Well this fixes the error but the class isn’t filled in:

[Null]

Got it fixed, this topic can be deleted

[ear1grey]

Huh? Thou speaketh in jest surely!