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1. Null
   Member

   Ok, I have searched the net for hours, but I couldn't get an answer for my question.

   If we use the for "each function" in php we can get a list of items like:
   Jack
   John
   Adrian
   Etc

   But the first name a want to have bold so it looks like:
   Jack
   John
   Adrian
   Etc

   Best way for me to do this, is to ad a class to the first name in the php code. But how do I do this? Cause the "for each" generates a list that is the same for eacht row (php/html code wise). So I only want the first name to be bold using a class (from a css) but all others not effected.

   Thx

   Posted 1 year ago #

2. ear1grey
   Member

   $class="special";
foreach($foo as $bar) {
echo("<p class='$class'>$bar</p>);
$class="";
}

   Posted 1 year ago #

3. chrishajer
   Moderator

   That is a very interesting short circuit. Thanks for that one ear1grey.

   Posted 1 year ago #

4. Null
   Member

   Euuhh well still can't get it to work...

   I have the function:
   function get_bb_menu() {
global $bbdb;
return $bbdb->get_results("SELECT * FROM $bbdb->menu WHERE set = 'active' ORDER BY order ASC");
}

   This will give (tabel sperated with - ):
   set - item - page - is - order
   active - Forums - index.php - is_front() - 0
   active - Statistic - statistics.php - is_bb_stats() - 1
   active - Search - search.php - is_bb_search() - 2

   Now I want this in a for each so it generates (note this is A PART what it should generate):

   <li><a <?php if (is_bb_search())
{
echo "id="current"";
}?> href="<?php option('uri'); ?>search.php">Search</a></li>
<li><a <?php if (is_bb_stats())
{
echo "id="current"";
}?> href="<?php option('uri'); ?>statistics.php">Statistics</a></li>

   But how to do this???

   Posted 1 year ago #

5. ear1grey
   Member

   That's very difficult to decipher, so for maintainability may I suggest you break out the code so you create variables first then use them when creating the echo statement.

   It looks like you need to use call_user_func(tabel["is"]) to run the function names that you're retrieving from the db.

   Posted 1 year ago #

6. Null
   Member

   I did that but you can't use php in an echo:

   <?php
global $bbdb;
$r = mysql_query("SELECT * FROM $bbdb->menu WHERE set = 'active' ORDER BY order ASC");
while($rw = mysql_fetch_array($r))
{
echo '<li><a href="'.$rw['page'].'">'.$rw['item'].'</a></li>';
}
?>

   This works perfectly, but now I want to add some php code into <a!here the php code!>...</a> so it will look like this (i only show the echo now):

   {
   echo<li><a <?php if ('.$rw['is'].')
{
echo "id="current"";
}?> href="<?php option('uri'); ?>'.$rw['page'].'">'.$rw['item'].'</a></li>;
   }`

   But this aint working cause you cant do php in an echo. Any suggestions?

   Posted 1 year ago #

7. ear1grey
   Member

   Just compute the computable stuff beforehand and it becomes a lot more maintainable/readable.

   // setup the basic data
$uri=option("uri").$rw["page"];
$class="";

   // compute the computable data
if ($rw['is']) { $class="current" }

   // write the line
echo "<li><a class='$current' href='$uri'>".$rw['item']."</a>"

   Note that I've used class rather than id for semantic purposes - the ID of an element shouldn't change, but it's class can change and can be multiple, so you could even do:

   $class="item";
if ($rw['is']) { $class .=" current" }

   Posted 1 year ago #

8. Null
   Member

   Hmm got this now:
   <?php
global $bbdb;
$r = mysql_query("SELECT * FROM $bbdb->menu WHERE set = 'active' ORDER BY order ASC");
while($rw = mysql_fetch_array($r))
$class="";
if ($rw['is']) { $class .=" current" }
{
echo '<li><a class="$current" href="'.$rw['page'].'">'.$rw['item'].'</a></li>';
}
?>

   But this gives me an error:
   Parse error: parse error, unexpected '}' on line 71

   Think I have misplaced something here?

   Greetz

   ps I didn't include $uri=option("uri").$rw["page"]; at all cause I wanted to test this first. So I keep it out for now...

   Posted 1 year ago #

9. ear1grey
   Member

   the while looks like it needs curly brackets adding to it or you're just going to repeatedly set $class="" then remove the curly bracket above the echo.

   Posted 1 year ago #

10. Null
    Member

    Can you give me a code example, cause i keep getting the error :(

    Posted 1 year ago #

11. ear1grey
    Member

    <?php
global $bbdb;
$r = mysql_query("SELECT * FROM $bbdb->menu WHERE set = 'active' ORDER BY order ASC");
while($rw = mysql_fetch_array($r)) <strong>{</strong>
$class="";
if ($rw['is']) { $class .=" current" }
echo '<li><a class="$current" href="'.$rw['page'].'">'.$rw['item'].'</a></li>';
}
?>

    Posted 1 year ago #

12. Null
    Member

    Still no luck :(
    I have this:
    <?php
global $bbdb;
$r = mysql_query("SELECT * FROM $bbdb->menu WHERE set = 'active' ORDER BY order ASC");
while($rw = mysql_fetch_array($r))
{
$class="";
if ($rw['is']) { $class .=" current" }
echo '<li><a class="$current" href="'.$rw['page'].'">'.$rw['item'].'</a></li>';
}
?>

    Which is the same code as yours, but I still get the error:
    Parse error: parse error, unexpected '}' on header.php on line 84

    And line 84 contains the if:
    if ($rw['is']) { $class .=" current" }

    I am totally lost here :S

    Posted 1 year ago #

13. ear1grey
    Member

    ...current"; }
    i.e.
    ...current"SEMICOLON }

    ?

    Posted 1 year ago #

14. Null
    Member

    Well this fixes the error but the class isn't filled in:

15. Forums

hmmm going to try something else, thx anyway